About the size of the bomb

[Starshine]

In Sunshine we see a spaceship that brings a big massive dark-matter bomb to the sun. This bomb is very huge, Capa compares it with Manhatten island. I thought: We know the size of Manhatten, so maybe it's possible to calculate the size of the bomb. It wouldn't be very accurately, but approximately right. We could imagine better the real size of the ship.

The problem: The stellar bomb is a cube and not flat like Manhatten. Is the whole surface of the bomb as big as the area of Manhatten or is just one of the 6 areas of the cube as big as Manhatten? What did Capa mean?

I guess the second possibility is probably right because it looks most suitable for such a comparison.
Another problem is that Manhatten isn't a square, that makes the calculations a bit unexactly because we can't calculate with the form of Manhatten island, we have to assume Manhatten is like a square, and that the bomb is a regular cube (it isn't 100% regular but nearly it is).


Here are my calculations:

59,5 km² = (7,714...Km)²

(7,714 km)³ = 45,028 km³ = Volume of the bomb

That's damn huge. It seems to be too huge. The whole ship would be almost 20 kilometers long!


If we assume Capa means that the area of Manhatten is as big as the whole area of the bomb-cube:

59,5 km² / 6 [areas of a cube] = 9,917...km²

9,917 km² = (3,149 km)²

(3,149 km)³ = 31,228...km³ = Volume of the bomb

This is also big but more realistic I think.
The ship would be approximately 7,8 km long (guessed factor: 2,5).
This is the best solution I got, but I am still working on it.





Hope you like it

[brittany]

Wow, nice research and illustration! LY!!!!!!

[Starry_MelC]

Whoa... o.O You deserve a LY for all the trouble! ;D

[cococi]

calculate the mass if ur on it ;D

hope i wrote mass right

[Starshine]

Thanks very much

For the mass I need to know what kind of stuff the bomb contains. And I dont know how big the room into the cube is (where Capa dies). I'm not sure whether I can ignore it. I'll think about it and a second part about the mass will follow maybe.

[cococi]

i think u can ignore the room he says "the bomb has a.... equivalent to manhatan island" so if u take that word by word ... i think u should try calculatin the mass considering its made out of a 1-5meter titanium outer shell whit an uranium core... could be a hidrogen bomb but i doubt it cause a hidrogen bomb wouldnt have any effect on a hidrogen star as large as the sun u could try also other kinds of explosvies if u dont think earth has taht much uranium.. ok iwich i doubt it .. um ok if im on it i gues i could try i got fiziques tomorow anywayz so...ur mats are prety compilcated ... u could've made it simpler but... so cosindering that only the "bomb" not including the space cause i wouldnt have to calculate the oxigen and the outher shell wich are 1/1000 of the bomb's size an infime part... makes it simpler


so taking ur 45,028 cubic kmers ok now u gota know uranium is outsandingly heavy its actualy 19.1 tones a cubic meter thats as big as a bath thub and as heavy as small plane .. or 3 tractors

so now we got a big problem cause dont think i can find an outher shell cause the sun's surface is a stagering 5519 thats 9940 degrees farenheit so...hehe got it so its the future they got a carbon outher shell that whitstands 4700 degrees celsius .. leets presume that in that point the sun's surface temperature is smaller so...
Carbon 2.267-3 grams per cub cmeter
uranium 19.100 kgs per cub meter
so lets say the outher shell /wall is 50meters long



441 cubic kmeters uranium core
uranium core is...8423100000000000kgrams ... do that in tones urself i gota get up at 6.30 (
ok the outher shell tomorow:D i gota sleep its aprox the size of the core cause carbon is super light hope the mats are correct so far

[Starshine]

I read something about "fissile matter" so the bomb must contain uran or plutonium. But it's a dark matter bomb and I have no idea how it works so I'm not sure what that stuff is.

I calculated the volume and the size of the bomb and for that I need the area of the outer shell. I tried to keep it as simple as possible, sry if it's complicated but I don't know how to write it more simple. For some math-operations there are now suitable symbols on my keybord (radical for example).

Thanks that you remind me that the bomb must have an outer shell, I tried to calculate the mass with a full massive uran cube and I got horrible high solutions.

The shield protects the bomb so the shell doesn't get 100% of the hotness in the sun because of the high speed of the bomb. The sunplasma floats around the shield and doesn't touchs the bomb (but after a time the shield were burned away of course). I think the shell isn't very strong and wide.

I think your carbon is a good idea, light and heat-resistant. But it could be also ceramic. Space Shuttles have it on their outer shell. A few meters ceramic would be pretty nice and it's cheap so they save money ;D

[kaliszewski]

I thought that in the Capa/Searle outtake on the U.K. DVD, Capa mentions that the bomb is five times the size of a football field (American football, I'm assuming.... ) with a mass equivalent to Manhattan Island. Just throwing that in the pot: I'd have to re-watch the scene to be sure, and I'm absolutely horrific at math at any rate....

[cococi]

maths for me are easy but u can't know for shure what tipe of bomb is now to finish the size of the outher shell ...btw if it's a dark matter bomb then the weight is 0 maibe negative becuase dark matter is undetectable by human the human technology spectrum so if it contains dark matter or inloves it calculating the weight is useless

the 50 meter outher shell i mentioned is 3tones per cub meter
its 50 meter because i tought that if the uranium would heat it would probably start the chain reaction before the bomb would be acitvated
Outher shell is 35,4 mil tones
the whole bomb is 8.423.100 mil tones -core +
35,4 mil tones shell- infime part of the bomb
thats 8.423.135,4 mil tones that is maibe actually as heavy as heavy as manhatan+1000 planes correct me if i did something wrong im sleepy im waiting for hunters mats

[Starshine]

What we now is: The bomb contains certain fissile matter, so we can take uranium. The puzzle is the ignition of the bomb, apparently the dark matter were created then on a strange way. I assure that actually Brain Cox doesn't know really how it works because we know almost nothing about dark matter and absolutely nothing about dark matter bombs of course. So we can assume the mass of uranium for our calculations.
All in all is this q-balls / dark-matter bomb scenario very ScFi-like.

Ok if we assume your 50 m - the mass:

[ from my 1st post]:
(3,149 km)³ = 31,228...km³ = Volume of the cube
^length of an edge

- (2 x 50 m) outer shell:

(3,49 km)³ = 42,509km³ = Volume of the bomb
^length of an edge

Mass = density x volume

27 km³ x 9160000000000 kg/km³ [density of uranium by wikipedia]

= 389.378.308.840 Tons

= 389.378 Million Tons

I toke the other solution in my first post which seems to be more realistic.

[cococi]

u shure mats are right ?
looks a little light to me where talking about 19 tones cub meter and 42 cub kmeters maibe i did it wrong ... just asking

[Starshine]

I were very sleepy but I still don't find a mistake. But I didn't assume 42 cubic kilometres, I took 31 which is my second solution from my first post.

Here is a nice drawing:
I drew the just the size of the base area of the cube, not the bomb.



So which one do you prefer ?

[cococi]

nice gg damn... Manhatan is big! i gues this thread is over.... lets get to a nother one shall we ;D ?

[Starshine]

Yeah gladly

[chero]

Here's a much deserved LY, TheHunter.